H=-10t^2+360t

Solution for H=-10t^2+360t equation:

=-10H^2+360H

We move all terms to the left:

-(-10H^2+360H)=0

We get rid of parentheses

10H^2-360H=0

a = 10; b = -360; c = 0;
Δ = b2-4ac
Δ = -3602-4·10·0
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-360)-360}{2*10}=\frac{0}{20}
=0
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-360)+360}{2*10}=\frac{720}{20}
=36
$